**Math help number4? - how to make sinker moulds**

A sample of the lead used to make that a lead weight for fishing is an initial temperature of 27.6 degrees Celsius and in a form immediately after it is poured melted.

how much energy is needed to melt at 0242 kg of lead? Assuming the specific heat and latent heat melting point of lead 128 J / kg C, 2.45 x 10 fourth with the J / kg and 327.3 respectively.answer in the unit C. J.

## 1 comment:

thgis part of the problem 2 is

1. SENSEable heat will increase the temperature to the melting temperature

2. latent heat is the phase-change --

Q = heat transfer in joules

Qsenseble + Q = Qlatent

Q = MCP (dt) + ml ------->

where m = mass

dt = change in temperature to the melting point

cp = sp heat

L = latent heat

from the same mass factor

Q = f (Cp (dt) + L)

Q = 242 kg (128J/kgC (327.3C-27.6C) + 2.45X10 ^ 4J/kg)

Q = 242 (128 (299.7) 2.45 x 10 ^ 4)

P = .242 (38.361,6 2.45 x 10 ^ 4)

P = .242 (62.861,6) = 1521.5072Joules = 1.52 x 10 ^ 4 Joules

I think that is right is certainly in the equation - but please, please read the calculations with the calculator - I have no

If the problem Doida

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Life.neighborhodd professor of engineering physics turned endly

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